In a common base circuit of a transistor,the amplification factor is $0.95.$ The base current when the emitter current is $2\,mA,$ is ....$mA$

For a $CE$ transistor amplifier,the audio signal voltage across the collector resistance of $2.0\,k\Omega$ is $2.0\,V$. Suppose the current amplification factor of the transistor is $100$. What should be the value of $R_B$ (in $k\Omega$) in series with $V_{BB}$ supply of $2.0\,V$ if the $dc$ base current has to be $10$ times the signal current?

In the study of a transistor as an amplifier,if $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$,where $I_{C}$,$I_{B}$,and $I_{E}$ are the collector,base,and emitter currents respectively,then:

In common emitter mode of a transistor, the current gain is $8$. The input impedance is $25 \, k\Omega$ and load resistance is $75 \, k\Omega$. The power gain is

For $I_b = 20 \ \mu A$ and $\beta = 100$,the value of the emitter current is ........ $mA$.

$A$ transistor oscillator is $(i)$ an amplifier with positive feedback,$(ii)$ an amplifier with reduced gain,$(iii)$ the one in which $dc$ supply energy is converted into an output energy. Then